杭电5842之Lweb and String

本文介绍了一道关于求解字符串转换后最长严格增子序列(LIS)的问题。目标是通过将字符串中的每个字母映射为自然数的方式,使得转换后的序列拥有尽可能长的严格增子序列。文章给出了示例并提供了AC代码实现。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >


Problem Description
Lweb has a string S.

Oneday, he decided to transform this string to a new sequence.

You need help him determine this transformation to get a sequence which has the longest LIS(Strictly Increasing).

You need transform every letter in this string to a new number.

A is the set of letters of S,B is the set of natural numbers.

Every injection f:AB can be treat as an legal transformation.

For example, a String “aabc”, A={a,b,c}, and you can transform it to “1 1 2 3”, and the LIS of the new sequence is 3.

Now help Lweb, find the longest LIS which you can obtain from S.

LIS: Longest Increasing Subsequence. (https://en.wikipedia.org/wiki/Longest_increasing_subsequence)
 

Input
The first line of the input contains the only integer T,(1T20).

Then T lines follow, the i-th line contains a string S only containing the lowercase letters, the length of S will not exceed 105.
 

Output
For each test case, output a single line "Case #x: y", where x is the case number, starting from 1. And y is the answer.
 

Sample Input
2 aabcc acdeaa
 

Sample Output
Case #1: 3

Case #2: 4

题意:智障题,统计一个只含小写字母的字符串里有多少种不同的字符

AC代码如下:

#include<iostream> #include <string> using namespace std; int main() { int t,i; int n; int num; int a[26]; int k = 1; string s; cin >> t; while (t--) { for (i = 0; i < 26; i++) { a[i] = 1; } num = 0; cin >> s; n = s.size(); for (i = 0; i < n; i++) { if (a[int(s[i]) - 'a']) { a[s[i] - 'a'] = 0; num++; } } cout<< "Case #"<<k++<<": "<< num << endl; }     return 0; }

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值