题目链接
https://www.patest.cn/contests/gplt/L1-040
AC代码
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <cstring>
#include <map>
#include <stack>
#include <set>
#include <cstdlib>
#include <ctype.h>
#include <numeric>
#include <sstream>
using namespace std;
typedef long long LL;
const double PI = 3.14159265358979323846264338327;
const double E = 2.718281828459;
const double eps = 1e-6;
const int MAXN = 0x3f3f3f3f;
const int MINN = 0xc0c0c0c0;
const int maxn = 1e5 + 5;
const int MOD = 1e9 + 7;
int main()
{
int n;
cin >> n;
while (n--)
{
char c;
double num;
scanf(" %c %lf", &c, &num);
if (c == 'M')
printf("%.2lf\n", (num * 1.0 / 1.09));
else
printf("%.2lf\n", num * 1.09);
}
}
本文提供了PATest CN竞赛题目L1-040的一个解题思路及C++实现代码,主要涉及货币单位转换的计算问题。通过读取输入并根据条件进行相应的数学运算来解决问题。

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