Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <231). It is guaranteed that the number of digits of Z is an even number.
Output Specification:
For each case, print a single line if it is such a number, or if not.Yes``No
Sample Input:
3
167334
2333
12345678
Sample Output:
Yes
No
No
#include <iostream>
using namespace std;
int main() {
int k;
string s;
int a, b, c;
cin >> k;
for (int i = 0; i < k; ++i) {
cin >> s;
a = stoi(s.substr(0, s.size() / 2));
b = stoi(s.substr(s.size() / 2));
c = stoi(s);
if (a * b != 0 && c % (a * b) == 0)
puts("Yes");
else
puts("No");
}
}
本文探讨一种数学性质:一个整数能否被其一半长度的两个数字相乘得到。通过实例展示如何切割并验证这种特性,并提供输入输出样例。主要关注的是编程实现,如C++代码检查整数是否满足此条件。
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