PAT甲级 1116 Come on! Let‘s C (20 分)

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这篇博客介绍了浙江大学举办的编程比赛'Let'sC'的有趣奖惩规则，冠军奖品神秘莫测，排名为素数的选手将获得小黄人，其余参赛者则享巧克力。展示了如何根据排名预测奖励并处理查询。

“Let’s C” is a popular and fun programming contest hosted by the College of Computer Science and Technology, Zhejiang University. Since the idea of the contest is for fun, the award rules are funny as the following:

0、 The Champion will receive a “Mystery Award” (such as a BIG collection of students’ research papers…).
1、 Those who ranked as a prime number will receive the best award – the Minions (小黄人)!
2、 Everyone else will receive chocolates.

Given the final ranklist and a sequence of contestant ID’s, you are supposed to tell the corresponding awards.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤10⁴), the total number of contestants. Then N lines of the ranklist follow, each in order gives a contestant’s ID (a 4-digit number). After the ranklist, there is a positive integer K followed by K query ID’s.

Output Specification:

For each query, print in a line ID: award where the award is Mystery Award, or Minion, or Chocolate. If the ID is not in the ranklist, print Are you kidding? instead. If the ID has been checked before, print ID: Checked.

Sample Input:

Sample Output:

8888: Minion
0001: Chocolate
1111: Mystery Award
2222: Are you kidding?
8888: Checked
2222: Are you kidding?

#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;
int ans[10000];// 0 没有  1 hava 2 checked 3 victory 4 prime
bool isprime(long long p) {
    for (long long i = 2; i * i <= p; ++i) {
        if (p % i == 0)
            return false;
    }
    return true;
}

int main() {
    long long n, m, num;
    cin >> n;
    for (int i = 1; i <= n; ++i) {
        cin >> num;
        if (i == 1)
            ans[num] = 3;
        else if (isprime(i)) {
            ans[num] = 4;
        } else
            ans[num] = 1;
    }
    cin >> m;
    for (int i = 1; i <= m; ++i) {
        cin >> num;
        printf("%04d: ", num);
        if (ans[num] == 1) {
            printf("Chocolate\n");
        } else if (ans[num] == 3)
            printf("Mystery Award\n");
        else if (ans[num] == 2)
            printf("Checked\n");
        else if (ans[num] == 4)
            printf("Minion\n");
        else if (!ans[num]) {
            printf("Are you kidding?\n");
            continue;
        }
        ans[num] = 2;

    }
    return 0;
}