Given three integers A, B and C in [−263,263], you are supposed to tell whether A+B>C.
Input Specification:
The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line Case #X: true
if A+B>C, or Case #X: false
otherwise, where X is the case number (starting from 1).
Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false
想用cin必须得每次输入clear一下,否则由于溢出的问题,输入数据会存在问题
#include <iostream>
using namespace std;
typedef long long LL;
int main() {
int N;
LL a, b, c;
cin >> N;
for (int i = 0; i < N; ++i) {
cin >> a;
cin.clear();
cin >> b;
cin.clear();
cin >> c;
cin.clear();
LL sum = a + b;
bool flag = false;
if (a > 0 and b > 0 and sum < 0)
flag = true;
else if (a < 0 and b < 0 and sum >= 0)
flag = false;
else if (sum > c)
flag = true;
if (flag)
cout << "Case #" << i + 1 << ": true" << endl;
else
cout << "Case #" << i + 1 << ": false" << endl;
}
return 0;
}
当然直接scanf就可以解忧愁了
#include <iostream>
using namespace std;
typedef long long LL;
int main() {
int N;
LL a, b, c;
cin >> N;
for (int i = 0; i < N; ++i) {
scanf("%lld %lld %lld", &a, &b, &c);
LL sum = a + b;
bool flag = false;
if (a > 0 and b > 0 and sum < 0)
flag = true;
else if (a < 0 and b < 0 and sum >= 0)
flag = false;
else if (sum > c)
flag = true;
if (flag)
cout << "Case #" << i + 1 << ": true" << endl;
else
cout << "Case #" << i + 1 << ": false" << endl;
}
return 0;
}
#include <iostream>
using namespace std;
long double a, b, c;
int main()
{
int T;
cin >> T;
for (int i = 1; i <= T; i ++ )
{
printf("Case #%d: ", i);
cin >> a >> b >> c;
if (a + b > c) puts("true");
else puts("false");
}
return 0;
}