问题发现
在使用newfixedThreadPool时设置核心线程10,最大线程20,采用arrayBlockingQueue10。
在for循环里打印i,以及线程id,发现线程的顺序是先打印1到10,然后打印21到30。也就是说后提交的数据中间输出。
提交优先级
提交优先级:就是先交付核心线程、等待队列、非核心线程。

代码如下:
public void execute(Runnable command) {
if (command == null)
throw new NullPointerException();
/*
* Proceed in 3 steps:
*
* 1. If fewer than corePoolSize threads are running, try to
* start a new thread with the given command as its first
* task. The call to addWorker atomically checks runState and
* workerCount, and so prevents false alarms that would add
* threads when it shouldn't, by returning false.
*
* 2. If a task can be successfully queued, then we still need
* to double-check whether we should have added a thread
* (because existing ones died since last checking) or that
* the pool shut down since entry into this method. So we
* recheck state and if necessary roll back the enqueuing if
* stopped, or start a new thread if there are none.
*
* 3. If we cannot queue task, then we try to add a new
* thread. If it fails, we know we are shut down or saturated
* and so reject the task.
*/
int c = ctl.get();
// worker数量比核心线程数小,直接创建worker执行任务
if (workerCountOf(c) < corePoolSize) {
if (addWorker(command, true))
return;
c = ctl.get

本文探讨了在使用Java线程池时遇到的问题,即线程的执行顺序并非按提交顺序进行。分析了线程池的工作原理,提交优先级遵循核心线程、等待队列、非核心线程的顺序,而执行优先级则是核心线程优先,接着是非核心线程,最后是等待队列中的任务。通过分析`execute`方法和`runWorker`方法的逻辑,揭示了线程调度的内部机制。
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