题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1003
代码如下:
#include<stdio.h>//hdu1003
int a[100005], dp[100005];
int main()
{
int T,n,max,s,e,ms,me;
scanf("%d",&T);
for(int k = 1; k<=T; k++)
{
scanf("%d",&n);
for(int i = 0; i<n; i++)
scanf("%d",&a[i]);
max = dp[0] = a[0], ms = me = s = e = 0;
for(int i = 1; i<n; i++)
{
if(dp[i-1]>=0)
{
dp[i] = dp[i-1] + a[i];
e = i;
}
else
{
dp[i] = a[i];
s = e = i;
}
if(dp[i]>max)
{
max = dp[i];
ms = s, me = e;
}
}
printf("Case %d:\n%d %d %d\n",k,max,ms+1,me+1);
}
return 0;
}