将色子的各个面作为1号面模拟一遍,并让其旋转四次,比较判断。
#include<stdio.h>
#include<string.h>
#define max 50
//模拟6个序号的面为1面
int arr[6][6]={{0,1,2,3,4,5},{1,5,2,3,0,4},{2,1,5,0,4,3},{3,1,0,5,4,2},{4,0,2,3,5,1},{5,4,2,3,1,0}};
bool rota(char cube2[], char cube1[])//以1-6为轴旋转90度(左->右)然后将两个色子比较
{
char temp;
for(int i=0; i<4; i++)
{
temp = cube2[1];
cube2[1] = cube2[2];
cube2[2] = cube2[4];
cube2[4] = cube2[3];
cube2[3] = temp;
if(strcmp(cube2, cube1)==0)
return true;
}
return false;
}
int main()
{
int judge;
char cube[max], cube1[max], cube2[max], str[max];
while(scanf("%s",str)!=EOF)
{
judge = 0;
for(int i=0; i<12; i++)//读取每个色子的颜色情况
{
if(i<6) cube[i] = str[i];
else cube1[i-6] = str[i];
}
for(int i=0; i<6 && judge == 0; i++)
{
for(int j=0; j<6; j++)
{
cube2[j] = cube[arr[i][j]];
}
if(rota(cube2, cube1))
{
judge = 1;
puts("TRUE");
break;
}
}
if(judge==0)
puts("FALSE");
}
return 0;
}
/*
Sample Input
rbgggrrggbgr
rrrbbbrrbbbr
rbgrbgrrrrrg
Sample Output
TRUE
FALSE
FALSE
*/