Train Seats Reservation

本文介绍了一种解决火车票预订冲突的算法,通过输入多个乘客的预订信息,包括起点站、终点站及所需座位数量,该算法能够计算出满足所有乘客需求所需的最少座位数,确保座位使用效率最大化。

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You are given a list of train stations, say from the station 111 to the station 100100100.

The passengers can order several tickets from one station to another before the train leaves the station one. We will issue one train from the station111 to the station 100100100 after all reservations have been made. Write a program to determine the minimum number of seats required for all passengers so that all reservations are satisfied without any conflict.

Note that one single seat can be used by several passengers as long as there are no conflicts between them. For example, a passenger from station111 to station 101010 can share a seat with another passenger from station 303030 to 606060.

Input Format

Several sets of ticket reservations. The inputs are a list of integers. Within each set, the first integer (in a single line) represents the number of orders,nnn, which can be as large as 100010001000. After nnn, there will be nnn lines representing the nnn reservations; each line contains three integers s,t,ks, t, ks,t,k, which means that the reservation needs kkk seats from the station sss to the station ttt .These ticket reservations occur repetitively in the input as the pattern described above. An integern=0n = 0n=0 (zero) signifies the end of input.

Output Format

For each set of ticket reservations appeared in the input, calculate the minimum number of seats required so that all reservations are satisfied without conflicts. Output a single star '*' to signify the end of outputs.

样例输入
2
1 10 8
20 50 20
3
2 30 5
20 80 20
40 90 40
0
样例输出
20
60
*
#include <stdio.h>
#include <string.h>
int a[1000];
int main(int argc, char *argv[])
{
	int t;
	while(scanf("%d",&t)!=EOF)
	{
		int i,j;
		if(t==0)
		{
			printf("*\n");
			break;
		}
		memset(a,0,sizeof(a));
		for(i=0;i<t;i++)
		{
			int c,d,e;
			scanf("%d %d %d",&c,&d,&e);
			for(j=c;j<d;j++)
			{
				a[j]+=e;		
			}
		}
		int max=-1;
		for(i=0;i<=100;i++)
		{
			if(max<a[i])
			{
				max=a[i];
			}
		}
		printf("%d\n",max);
	}
	return 0;
}
资源下载链接为: https://pan.quark.cn/s/22ca96b7bd39 在C#开发中,Windows Media Player控件是集成音频和视频播放功能的强大工具。本文将介绍如何在C#中实现不同的播放模式,如随机播放、列表循环和单曲循环,这些功能在多媒体应用中十分常见 。 要使用Windows Media Player控件,首先需要将其添加到C#项目中。在Visual Studio中,可以通过在工具箱中搜索“Windows Media Player”,并将其拖放到窗体上完成 。接着,设置控件的基本属性,如URL,以指定要播放的媒体文件 。 随机播放模式会在一首歌曲播放结束后,随机选择播放列表中的下一首歌曲。可以通过创建一个包含所有歌曲URL的数组,并利用Random类生成随机索引来实现。例如: 列表循环模式会在一首歌曲播放结束后,自动从播放列表的开头重新开始播放。实现方法是检测到播放结束后,将URL重置为列表的第一个元素: 单曲循环模式则是在一首歌曲播放结束后,重新播放当前歌曲。可以通过将播放器的当前播放位置重置为0并重新播放来实现: 以上代码均需在windowsMediaPlayer1_PlayStateChange事件处理器中实现,该事件会在播放器的播放状态改变时触发 。需要注意的是,这些示例假设已正确引用了WMPLib命名空间,并且Windows Media Player控件的ID为“windowsMediaPlayer” 。 在实际应用中,除了实现播放模式外,还可能需要考虑错误处理、用户界面更新等因素。为了使播放列表更具动态性,可以考虑从数据库或XML文件加载歌曲信息,而不是硬编码在代码中,从而提升用户体验 。通过这些方法,可以在C#中灵活实现Windows Media Player的各种播放模式,满足不同多媒体应用场景的需求 。
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