腾讯举办的一场比赛——1002. Love Story

最新推荐文章于 2021-12-01 21:36:23 发布

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本文提供了一段C++代码，用于计算二维平面上两个不相交矩形之间的最短距离。该算法通过遍历矩形顶点并考虑边平行情况下的最小垂直距离来实现。

就是求坐标系内两个矩形的最短距离，这两个矩形一定是分离的，没有相交，没有相切，也没有包含。

没学过ACM几何算法的也可以做。
直接贴代码。

#include <set>
#include <map>
#include <list>
#include <stack>
#include <queue>
#include <cmath>
#include <cstdio>
#include <vector>
#include <iomanip>
#include <cstring>
#include <cstdlib>
#include <iostream>
#include <algorithm>
using namespace std;

double dis(double a, double b, double c, double d)
{
    return sqrt((a - c) * (a - c) + (b - d) * (b - d));
}

int main()
{
    int t;
    
    scanf("%d", &t);
    while (t--)
    {
        double x1[4], x2[4], y1[4], y2[4];
        double mi = 400000;
        for (int i = 0; i < 2; i++)
        {
            scanf("%lf%lf", &x1[i], &y1[i]);
        }
        for (int i = 0; i < 2; i++)
        {
            scanf("%lf%lf", &x2[i], &y2[i]);
        }
        x1[2] = x1[0];
        x1[3] = x1[1];
        y1[2] = y1[1];
        y1[3] = y1[0];
        x2[2] = x2[0];
        x2[3] = x2[1];
        y2[2] = y2[1];
        y2[3] = y2[0];
        for (int i = 0; i < 4; i++)
        {
            for (int j = 0; j < 4; j++)
            {
                mi = min(mi, dis(x1[i], y1[i], x2[j], y2[j]));
            }
        }
        if (x2[0] < x2[1])
        {
         if ((x1[0] > x2[0] && x1[0] < x2[1]) || (x1[1] > x2[0] && x1[1] < x2[1]) || (x2[0] > x1[0] && x2[0] < x1[1]) || (x2[1] > x1[0] && x2[1] < x1[1]))
         {
             double a = min(fabs(y1[0] - y2[0]), fabs(y1[0] - y2[1]));
             double b = min(fabs(y1[1] - y2[0]), fabs(y1[1] - y2[1]));
             a = min(a, b);
             mi = min(mi, a);
         }
        }
        else
        {
         if ((x1[0] > x2[1] && x1[0] < x2[0]) || (x1[1] > x2[1] && x1[1] < x2[0]) || (x2[0] > x1[1] && x2[0] < x1[0]) || (x2[1] > x1[1] && x2[1] < x1[0]))
         {
             double a = min(fabs(y1[0] - y2[0]), fabs(y1[0] - y2[1]));
             double b = min(fabs(y1[1] - y2[0]), fabs(y1[1] - y2[1]));
             a = min(a, b);
             mi = min(mi, a);
         }
        }
        if (y2[0] < y2[1])
        {
         if ((y1[0] > y2[0] && y1[0] < y2[1]) || (y1[1] > y2[0] && y1[1] < y2[1]) || (y2[0] > y1[0] && y2[0] < y1[1]) || (y2[1] > y1[0] && y2[1] < y1[1]))
         {
             double a = min(fabs(x1[0] - x2[0]), fabs(x1[0] - x2[1]));
             double b = min(fabs(x1[1] - x2[0]), fabs(x1[1] - x2[1]));
             a = min(a, b);
             mi = min(mi, a);
         }
        }
        else
        {
         if ((y1[0] > y2[1] && y1[0] < y2[0]) || (y1[1] > y2[1] && y1[1] < y2[0]) || (y2[0] > y1[1] && y2[0] < y1[0]) || (y2[1] > y1[1] && y2[1] < y1[0]))
         {
             double a = min(fabs(x1[0] - x2[0]), fabs(x1[0] - x2[1]));
             double b = min(fabs(x1[1] - x2[0]), fabs(x1[1] - x2[1]));
             a = min(a, b);
             mi = min(mi, a);
         }
        }
        printf("%.4lf\n", mi);
    }
    
    return 0;
}