Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public ListNode swapPairs(ListNode head) {
//if(head==null){return null;}
ListNode temp ;
if(head!=null&&head.next!=null){
temp=head.next;
head.next=temp.next;
temp.next=head;
head=temp;
ListNode node0=head.next;
while(node0.next!=null&&node0.next.next!=null){
temp=node0.next;
node0.next=temp.next;
temp.next=node0.next.next;
node0.next.next=temp;
node0=node0.next.next;
}
}
return head;
}
本文介绍了一种链表相邻节点交换算法,包括其基本原理、实现步骤和代码实例。
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