1037 Magic Coupon java

最新推荐文章于 2021-01-24 13:27:43 发布

有梦就不怕痛

最新推荐文章于 2021-01-24 13:27:43 发布

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分类专栏：贪心算法 Java学习

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博客围绕火星魔法商店的优惠券和商品价值展开，介绍了使用不同N值的优惠券与商品搭配的规则，目标是使获利最大化。给出了输入规格、输出规格及示例，需根据给定的优惠券和商品价值数据，计算能获得的最大金额。

The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also offers some bonus product for free. However, if you apply a coupon with a positive N to this bonus product, you will have to pay the shop N times the value of the bonus product... but hey, magically, they have some coupons with negative N's!

For example, given a set of coupons { 1 2 4 −1 }, and a set of product values { 7 6 −2 −3 } (in Mars dollars M$) where a negative value corresponds to a bonus product. You can apply coupon 3 (with N being 4) to product 1 (with value M$7) to get M$28 back; coupon 2 to product 2 to get M$12 back; and coupon 4 to product 4 to get M$3 back. On the other hand, if you apply coupon 3 to product 4, you will have to pay M$12 to the shop.

Each coupon and each product may be selected at most once. Your task is to get as much money back as possible.

Input Specification:

Each input file contains one test case. For each case, the first line contains the number of coupons NC, followed by a line with NCcoupon integers. Then the next line contains the number of products NP, followed by a line with NP product values. Here 1≤NC,NP≤105, and it is guaranteed that all the numbers will not exceed 230.

Output Specification:

For each test case, simply print in a line the maximum amount of money you can get back.

Sample Input:

Sample Output:

import java.util.Arrays;
import java.util.Scanner;

public class Main {
    /**
     * 用scanner,有一组数据超时
     * 用BufferedReader，第二组数据错误，还有一组数据有时候超时，有时候不超时
     * 我用scanner
     * */
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt();
        int[] nc = new int[n];
        for (int i=0; i<n; ++i) {
            nc[i] = scanner.nextInt();
        }
        int m = scanner.nextInt();
        int[] mp = new int[m];
        for (int j=0; j<m; ++j) {
            mp[j] = scanner.nextInt();
        }
        Arrays.sort(nc);
        Arrays.sort(mp);
        int sum = 0;
        int i=0, j = m-1;
        while(i<n && i<m && nc[i]<0 &&mp[i]<0) {
            sum = sum + nc[i]*mp[i];
            ++i;
        }
        i = n-1;
        while (i>=0 && j>=0 && nc[i]>0 && mp[j]>0) {
            sum = sum + nc[i]*mp[j];
            --i;
            --j;
        }
        System.out.println(sum);



    }
}