Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [−2,1,−3,4,−1,2,1,−5,4],
the contiguous subarray [4,−1,2,1] has the largest sum = 6.
class Solution {
public:
int maxSubArray(int A[], int n) {
if(n <= 0)return 0;
for(int i = 1; i < n; i++)
A[i] += A[i - 1];
int maxsum = INT_MIN;
int minsum = 0;//最开始minsum为0
for(int i = 0; i < n; i++)
{
maxsum = max(maxsum, A[i] - minsum);//先计算当前的最大值再更新 minsum
minsum = min(minsum, A[i]);
}
return maxsum;
}
};

本文介绍了一种算法来找到给定数组中具有最大和的连续子数组,通过使用前缀和数组和动态更新最小前缀和,提高了查找效率。
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