Problem E
All in All
Input: standard input
Output: standard output
Time Limit: 2 seconds
Memory Limit: 32 MB
You have devised a new encryption technique which encodes a message by inserting between its characters randomly generated strings in a clever way. Because of pending patent issues we will not discuss in detail how the strings are generated and inserted into the original message. To validate your method, however, it is necessary to write a program that checks if the message is really encoded in the final string.
Given two strings s and t, you have to decide whether s is a subsequence of t, i.e. if you can remove characters from t such that the concatenation of the remaining characters is s.
Input Specification
The input contains several testcases. Each is specified by two strings s, t of alphanumeric ASCII characters separated by whitespace. Input is terminated by EOF.
Output Specification
For each test case output, if s is a subsequence of t.
Sample Input
sequence subsequence
person compression
VERDI vivaVittorioEmanueleReDiItalia
caseDoesMatter CaseDoesMatter
Sample Output
Yes
No
Yes
No
水题:
#include<cstdio> #include<string> #include<iostream> using namespace std; int main() { string s1,s2; while(cin>>s1>>s2) { int j=0; for(int i=0;i<s2.length();i++) { if(s2[i]==s1[j]) j++; } if(j==s1.length()) printf("Yes\n"); else printf("No\n"); } return 0; }
本文介绍了一个简单的算法,用于判断一个字符串是否为另一个字符串的子序列。通过遍历两个字符串并对比字符来实现这一功能,该算法可以应用于加密技术中验证消息的有效性。
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