pow_doub.cpp

C++运算符重载示例

  name="google_ads_frame" marginwidth="0" marginheight="0" src="http://pagead2.googlesyndication.com/pagead/ads?client=ca-pub-5572165936844014&dt=1194442938015&lmt=1194190197&format=336x280_as&output=html&correlator=1194442937843&url=file%3A%2F%2F%2FC%3A%2FDocuments%2520and%2520Settings%2Flhh1%2F%E6%A1%8C%E9%9D%A2%2FCLanguage.htm&color_bg=FFFFFF&color_text=000000&color_link=000000&color_url=FFFFFF&color_border=FFFFFF&ad_type=text&ga_vid=583001034.1194442938&ga_sid=1194442938&ga_hid=1942779085&flash=9&u_h=768&u_w=1024&u_ah=740&u_aw=1024&u_cd=32&u_tz=480&u_java=true" frameborder="0" width="336" scrolling="no" height="280" allowtransparency="allowtransparency"> #include <iostream.h>

class pwr {
   double b;
   int e;
   double val;
 public:
   pwr(double base, int exp);
   pwr operator+(pwr obj)
   {
      double base;
      int exp;
      base = b + obj.b;
      exp = e + obj.e;
      pwr temp(base, exp);
      return temp;
   }
   operator double(void) {return val;}     // converts to double
 };

pwr::pwr(double base, int exp)
 {
   b = base;
   e = exp;
   val = 1;
   if (exp!=0)
      while(exp-- > 0)
         val *= b;
 }


void main(void)
 {
   pwr pwr1(4.0, 2);
   double doub1;

   doub1 = pwr1;                  // convert x to double
   cout << (doub1 + 100.2) << endl;

   pwr pwr2(3.3, 3), pwr3(0,0);
   pwr3 = pwr1 + pwr2;              // no conversion
   doub1 = pwr3;                  // convert to double
   cout << doub1;
 }

 

 

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