直接看下面的solution2,书中p263-264说明挺好a
##Solution1:
自己想出来的笨蛋算法!
class Solution {
public:
vector<int> multiply(const vector<int>& A) {
vector<int> B;
for(int i = 0; i < A.size(); i++){
B.push_back(my_multiply(A, i));
}
return B;
}
int my_multiply(const vector<int>& A, int k) {
int result = 1;
for(int i = 0; i < A.size(); i++) {
if(i == k) ;
else
result *= A[i];
}
return result;
}
};
##Solution2:
参考网址:https://www.nowcoder.com/profile/1878117/codeBookDetail?submissionId=13951708
认真捋一捋,确实快不少~~~
class Solution {
public:
vector<int> multiply(const vector<int>& A) {
int n = A.size(), temp = 1;
vector<int> B(n, 1);
if(n > 0) {
//计算下三角连乘
for(int j = 1; j < n; j++) {
B[j] = B[j-1] * A[j-1];
}
for(int k = n-2; k >= 0; k--) {
temp = temp * A[k+1];
B[k] = B[k] * temp;
}
}
return B;
}
};