Given a binary tree, return the inorder traversal of its nodes' values.
For example:
Given binary tree {1,#,2,3}
,
1 \ 2 / 3
return [1,3,2]
.
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
struct TreeNode
{
int val;
TreeNode *left;
TreeNode *right;
TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};
class Solution {
public:
std::vector<int> inorderTraversal(TreeNode *root) {
dfs(root);
return res;
}
private:
std::vector<int> res;
void dfs(TreeNode *root)
{
if(root != NULL)
{
dfs(root->left);
res.push_back(root->val);
dfs(root->right);
}
}
};