思路:碰到不是相同的元素,记录下来(因为数组已排序,更方便求解)
code:
class Solution {
public:
int removeDuplicates(int A[], int n) {
if(n<=1)return n;
int index = 0;
for(int i=0;i<n-1;i++)
if(A[i] != A[i+1])
A[index++] = A[i];
A[index++] = A[n-1];
return index;
}
};