字符串水题 N - ?(>_o)!

Submit Status Practice ZOJ 3775

Description

?(>_o)! is a pseudo-object-oriented programming language. It implements the following commands:

Command	Description
?	Check whether the character '?' is in the program's source code. If '?' does not exist in the program's source, the hardware will catch fire or explode.
(	It tries to match ')', although mismatch of brackets does not matter at all.
>	Increase the internal accumulator.
_	Print the program's source code.
o	Instantiate an object of a new sub class of the generic super class. Due to the best principles of object hiding, this object cannot be accessed in any way.
)	Just matches '('. It's for patient with obsessive-compulsive disorder. However, mismatch of brackets does not matter at all.
!	Print "Hello, world!".
Other characters	Be treated as comments rather than instruction.

However, it's only another joke programming language. There is even no way to access the accumulator. But it's one of easiest to finish a "Hello world" program or a quine program. A quine is a computer program which takes no input and produces a copy of its own source code as its only output. Your task is to judge whether a ?(>_o)! program is a quine.

Input

There are multiple test cases. The first line of input is an integer T indicates the number of test cases. For each test case:

There is one line of string represents the source code of a ?(>_o)! program. The program contains no more than 256 characters. The ASCII value of each character is within [32, 126].

Output

For each test case, output "Yes" if it is a quine. Otherwise, output "No".

Sample Input

4
Hello, world!
source_code
source__code
?(>_o)!

Sample Output

Yes
Yes
No
No

Hint

The output of the four sample programs are {"Hello, world!", "source_code", "source__codesource__code", "?(>_o)!Hello, world!"} respectively. Therefore the first two programs are quines, and the last two are not.

Luckily, there is a '?' in the fourth program, so the hardware will not catch fire or explode during running the fourth program.

题目的意思大致就是：

这个题目的其他字符都没有多大的意思，只要看' _ ' 和 ' ! '就好了。

1.当出现一个下划线' _ '时，表示把该字符串再输出一次。

2.当出现一个叹号时，表示打印一个" Hello, world! " 这个字符串。

注意这里的hello world 这里有个空格，所以读入时不能用scanf("%s",a);

所以要用gets(a); 来读入；

当新输出的字符串与旧的字符串完全相同的时候，那么就输出"Yes "；

else 输出 No

这道题主要是考察怎样把一个字符串复制到另一个中去。

 

#include<stdio.h>
#include<string.h>
int main(){
	int T,i,j,len;
	char str[300],a[]="Hello, world!";
	scanf("%d",&T);
	getchar();
	while(T--){
		//注意这里要用gets，要不然的话遇到空格不会继续读入； 
		gets(str);
		len=strlen(str);
		int num1=0,num2=0;
		for(i=0;i<len;i++){
			if(str[i]=='!') num1++;
			else if(str[i]=='_')  num2++;
		}
		//首先判断'_'字符的个数，如果大于1的话，那么肯定是不存在的； 
		if(num2>1)  {puts("No"); continue;}
		//如果'_'字符的个数只有一个，但是'!'的个数没有的话，那么也是存在的 
		if(num2==1 && !num1)  {puts("Yes"); continue;}
		char ss[10000];
		int k=0;
		while(num1--){
			//这里的13代表的是hello world中字符的个数；
			//这里的目的就是把hello world这个字符串复制过去，直接复制的话好像会有问题； 
			for(i=0;i<13;i++)
			ss[k++]=a[i];
		}
		ss[k]='\0';
		printf("%s\n",strcmp(ss,str)==0?"Yes":"No");
	}
}

注意这里的hello world 这个字符串的复制。

其实不用函数strcat，直接数出来该字符串的字符的个数，然后再复制到另一个中去。