7-6 别再来这么多猫娘了！

输入样例1:

5
MaoNiang
SeQing
BaoLi
WeiGui
BuHeShi
4
BianCheng MaoNiang ba! WeiGui De Hua Ye Keyi Shuo! BuYao BaoLi NeiRong.

输出样例1:

BianCheng <censored> ba! <censored> De Hua Ye Keyi Shuo! BuYao <censored> NeiRong.

输入样例2:

5
MaoNiang
SeQing
BaoLi
WeiGui
BuHeShi
3
BianCheng MaoNiang ba! WeiGui De Hua Ye Keyi Shuo! BuYao BaoLi NeiRong.

输出样例2:

3
He Xie Ni Quan Jia!

输入样例3:

2
AA
BB
3
AAABBB

输出样例3:

<censored>A<censored>B

输入样例4:

2
AB
BB
3
AAABBB

输出样例4:

AA<censored><censored>

输入样例5:

2
BB
AB
3
AAABBB

#include <bits/stdc++.h>
using namespace std;
typedef long int ll;
const int N = 1e6 + 10;
void solve()
{
    int n;
    cin>>n;
    string ban[n];
    for(int i=0;i<n;i++) cin>>ban[i];
    int mx,cnt=0;
    cin>>mx;
    cin.ignore();
    string aa;
    getline(cin,aa);
    string re="===";
    for(int i=0;i<n;i++)
    {
        int k=aa.find(ban[i]);
        while(k!=-1)
        {
            aa.replace(aa.begin()+k,aa.begin()+k+ban[i].length(),re);
            cnt++;
            k=aa.find(ban[i]);
        }
    }
    int k=aa.find(re);
    while(k!=-1)
    {
        aa.replace(aa.begin()+k,aa.begin()+k+re.length(),"<censored>");
        k=aa.find(re);
    }
    if(cnt>=mx)
        cout<<cnt<<endl<<"He Xie Ni Quan Jia!";
    else cout<<aa;
}
signed main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    int t = 1;
    while (t--)
    {
        solve();
    }
    return 0;
}