The factorial of an integer N, written N!, is the product of all the integers from 1 through N inclusive. The factorial quickly becomes very large: 13! is too large to store in a 32-bit integer on most computers, and 70! is too large for most floating-point variables. Your task is to find the rightmost non-zero digit of n!. For example, 5! = 1 * 2 * 3 * 4 * 5 = 120, so the rightmost non-zero digit of 5! is 2. Likewise, 7! = 1 * 2 * 3 * 4 * 5 * 6 * 7 = 5040, so the rightmost non-zero digit of 7! is 4.
PROGRAM NAME: fact4
INPUT FORMAT
A single positive integer N no larger than 4,220.SAMPLE INPUT (file fact4.in)
7
OUTPUT FORMAT
A single line containing but a single digit: the right most non-zero digit of N! .SAMPLE OUTPUT (file fact4.out)
4
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
int main()
{
FILE *fin,*fout;
fin=fopen("fact4.in","r");
fout=fopen("fact4.out","w");
int N,sum;
fscanf(fin,"%d",&N);
sum=1;
while(N>1){
sum*=N;
while(sum%10==0)
sum/=10;
sum%=100000;
N--;
}
sum%=10;
fprintf(fout,"%d\n",sum);
return 0;
}
一开始蠢了。。居然直接取最后一个的非0位。。