嵌入式

#include <stdio.h>#include <string.h>#include <stdlib.h>void my_toupper(char * str){ while(*str != '\0') { if((*str >= 'a') && (*str <= 'z')) *str += 'A' - 'a'; str++; } retur

#include <stdio.h>#include <stdlib.h>/*-------------------- 排序规则 -------------------- 它的工作原理是每一次从待排序的数据元素中选出 最小（或最大）的一个元素，存放在序列的起始位 置，直到全部待排序的数据元素排完。 稳定性:选择排序是不稳定的排序方法 如:[5,5,3]-------------------------------------------------*/

#include <stdio.h>int main(int argc, const char *argv[]){ char *str = "87a8dfs4dsfdjskl\ afdsjklsadfjkl;kjassfdjklasdfkl\ djfffffffffffffffffffffffffdfdj\ dfjasdddddddddddddddddddddddddd\ djas;lkeafidjfdkadsjadfsfd

#include <stdio.h>#include <math.h>#define N 2.6int main(){ float x; float y; float r = 20; int i; for (x = -r; x <= r; x++) { y = sqrt(r*r - x*x) * N; for (i = 0; i < r*N - y; i++) putchar(' '); for (i = 0; i < y

#include <stdio.h>#define N (1024)#define DIGIT 'd'#define UPER 'U'#define LOWER 'L'#define DEBUG 0int state = 0;int max = 0;int count = 0;int get_data(char *dest, int num){ char ch; int

#include <stdio.h>#include <math.h>#define BC '.'#define FC '0'void show_color_char(int ch, int fcolor, int bcolor){ fcolor %= 10; bcolor %= 10; /*background color is ignored */ printf("\e[1;3%dm%c\e[0m", fcolor, ch);// putchar(ch)

#include <stdio.h>#define BUFF_SIZE (1024)void swap(char *head, char *tail){ while (head < tail) { *head ^= *tail; *tail ^= *head; *head ++ ^= *tail --; }}int reverse_word(char *str){ char *head = str, *tail = str; whi

#include <stdio.h>//排序函数，分别对每一行的元素进行排序void sort_d_array(int (*a)[4], int row, int col){ int i,j,k,temp; for(i=0; i<row; i++) { for(k=0; k<col; k++) { for(j=0; j<col-k-1; j++) {

#include <stdio.h>#include <string.h>#define N 20void sort_data(char *const src,const unsigned int n){ int i,j; for(i = 0; i < n - 1; i ++) { for(j = 0; j < n - i - 1; j ++ ) { if(src[j] > src[j + 1]) { src[j] ^=

#include <stdio.h>#include <string.h>#include <stdlib.h>#include <dirent.h>#include <sys/types.h>int get_file_num(char* root){ int total = 0; DIR* dir = NULL; // 打开目录 dir = opendir(root); // 循环从目录中读文件 char path[1

#include <stdio.h>int main(int argc, const char *argv[]){ int i,j; int nu; puts("input your number:"); while(1 != scanf("%d",&nu)) getchar(); for(i = 0; i < nu; i ++) { for(j = nu - i; j > 0; j --) putchar('.'); for(j =

#include <stdio.h>int test01(){ int a2[2][10];//a2是一个二维数组，这个二维数组中包含两个一维数组，a2[0],a2[1],a2[0]和a2[1]两个数组是连续的 int index = 0; int i, j; for (i = 0; i < 2; i++) { for (j = 0; j < 10; j++) { a2[i][j] = index++; } }//遍历一个二维数组，把数组中每个成员

#include <stdio.h>#include <string.h>int main(){ char a[100] = "12+5=;45-2=;34*2=;56/3="; char b[100] = { 0 }; char *s = strtok(a, ";"); while(s) { int i, j; char c; sscanf(s, "%d%c%d=", &i, &

#include <stdio.h>#include <stdlib.h>#define N 32int main(int argc, const char *argv[]){ int i,j; char ch[N * 4] = { /* 以下是 '我' 的 16点阵宋体 字模，32 byte */ 0x06,0x40,0x38,0x50,0x08,0x48,0x08,0x48, 0x08,0x40,0xFF,0xFE,0x08,0x40,0x08,

#include <stdio.h>#include <stdlib.h>char hex_char(unsigned int n ){ switch (n) { case 0: return '0'; case 1: return '1'; case 2: return '2'; case 3: return '3'; case 4: re

#include <stdio.h>#include <stdlib.h>int main(int argc, const char *argv[]){// //验证*号是什么// int i;// for(i = 0; i < argc; i++)// printf("%s\n", argv[i]);// return 0; if (argc < 4) { fprintf(stde

#include <stdio.h>void hannuota(int n, char A, char B, char C){/* 如果是1个盘子 直接将A柱子上的盘子从A移到C 否则 先将A柱子上的n-1个盘子借助C移到B 直接将A柱子上的盘子从A移到C 最后将B柱子上的n-1个盘子借助A移到C*/ if (1 == n) { printf("将编号为%d的盘子直接从%c柱子移到%c柱子\n", n, A, C); } else { hannuo

#include <stdio.h>#include <stdlib.h>#include <time.h>//计算机的时钟是不停改变的一个值//time函数是c语言的库函数，功能是得到系统当前时间int main(int argc, const char *argv[]){ int a; int i; time_t tm = time(NULL); //只要种子不同，rand产生的随机数就不同，如果种子一样，那么rand产生的随机数就一样

#include <stdio.h>#include <math.h>#include <stdlib.h>int main(int argc, const char *argv[]){ if(argc < 2) { fprintf(stderr, "Usage %s <number>\n", argv[0]); exit(1); } int num,i; for(num =

#include <stdio.h>#include <stdlib.h>int mystrlen(const char *s){ int len = 0; while(s[len]) { len++; } return len;}int mypow10(int n)//得到10的n次方{ if (n == 0) return 1; if (n == 1) retu

#include <stdio.h>int main(int argc, char *argv[]){ int a[] = {169, 22, 323, 515, 618, 297, 1596, 123, 59, 1674}; int i; int tmp = a[0];//默认数组中第一个成员就是最大的 for(i = 1; i < sizeof(a) / sizeof(a[0]); i++)//最大成员 { if (a[i]

#include <stdio.h>#include <stdlib.h>int swap_data(int method){ int x = 11; int y = 22; int tmp = -1; switch(method) { case 1: tmp = x; x = y; y = tmp;

测试代码#include <unistd.h>#include <stdlib.h>#include <stdio.h>#include <string.h>int four_char_to_int(unsigned char a, unsigned char b, unsigned char c, unsigned char d){ unsigned int ret_val = 0; ret_val = d; ret

使用联合体可以实现浮点型数据与字符型数据的数据共享，首先需要测试一下自己的系统的浮点型数据和字符型数据所占有的内存空间，然后分配一个同等大小的字符型数据的数组。由于两个变量的共享同一块内存空间，对浮点型数据的操作，实际上就是对字符型数组的操作，最后完成自己需要的转换。测试代码#include <unistd.h>#include <stdlib.h>#include <stdio.h>#include <string.h>#define R2D

#include <stdio.h>#include <unistd.h>#include <stdlib.h>#include <sys/types.h>#include <sys/stat.h>#include <string.h>#include <sys/time.h>#include <sys/resource.h>void printf_linux_res(const char* n

size_t strftime(char *s, size_t max, const char *format, const struct tm *tm);功能：把YYYY-MM-DD HH:MM:SS格式的日期字符串转换成其它形式的字符串。参数： char *s：存储转换格式的首地址 size_t max：s的最大值 const char *format：格式 const struct tm *tm：时间它可以用以下的符号对日期和时间进行格式化：%d 日期, 01-31%f

一定要使用root权限运行此程序编译时加上 -lcrypt 选项#include <stdio.h>#include <sys/types.h>#include <fcntl.h>#include <shadow.h>#include <unistd.h>#include <string.h>#include <crypt.h>#define _XOPEN_SOURCE int main(int a

#include <stdio.h>#include <sys/types.h>#include <sys/types.h>#include <grp.h>#include <unistd.h>#if 0 struct group { char *gr_name; /* group name */ char *gr_passwd; /* gr

#include <stdio.h>#include <sys/types.h>#include <string.h>int trim_dots(const char * path){ char * pos = NULL; pos = strrchr(path, '/'); printf("%s\n", pos); if(pos == NULL) { perror("strrchr");

#include <stdio.h>#include <sys/types.h>#include <pwd.h>#if 0 struct passwd { char *pw_name; /* username */ char *pw_passwd; /* user password */ uid_t pw_uid; /* user ID */ gid_t pw_gid;

/* #include <glob.h> int glob(const char *pattern, int flags, int (*errfunc) (const char *epath, int eerrno), glob_t *pglob); void globfree(glob_t *pglob);功能：Linux文件系统中路径名称的模式匹配

#include <stdio.h>#include <stdlib.h>#include <unistd.h>#include <string.h>#include <errno.h>#include <sys/types.h>#include <sys/stat.h>#include <fcntl.h>#define MAX_BUFF_SIZE (1024)int create_big

/* 删除文件的指定行 *///删除一个文件的注释#include <stdio.h>#include <stdlib.h>#include <unistd.h>#include <string.h>#include <stddef.h>#include <errno.h>#define MAX_BUFF_SIZE (1024)int del_comment(void){ FILE *fp_

#include <stdio.h>int main(){ char ch = 'F'; ch = getchar(); int i,j; for(i = 0; i <= ch - 'A'; i ++) { for(j = 0; j < i ; j ++) putchar('_');#if 1 for(j = 0; j <= i; j ++) putchar(ch - j);#endif putchar(10); } retu

#include <stdio.h>#define BUFF_SIZE 1024int int2string(int value, char *buff);int main(int argc, const char *argv[]){ int value = -98765432; char buff[BUFF_SIZE]; int2string(value, buff); puts(buff); return 0;}int int2string(int val

测试代码#include <stdio.h>#define BUFF_SIZE 32#define IS_DIG(_ch_) (_ch_ >= '0' && _ch_ <= '9')#define IS_DOT(_ch_) ('.' == _ch_)int ip2int(const char *ipstr, int *ipbuff);int main(int argc, const char *argv[]){ char buff[BUFF_S

测试代码#include <stdio.h>#define OPTIMIZE 0#if OPTIMIZEvoid *mymemcpy(void *dest, const void *src, int nbyte){ register int *d4 = dest; register const int *s4 = src; register char *d1; register const char *s1; register int n = nbyte >&gt

测试代码#include <stdio.h>//#define IS_LOWER(CH) (CH >= 'a' && CH <= 'z')/* 定义一个和变量CH相同类型的临时变量_ch_,判断两者类型是否一致，不一致给出一个警告 */#define IS_LOWER(CH) ({\ typeof(CH) _ch_ = CH;\ _ch_ >= 'a' && _ch_ <= 'z';\ })int is_lower

测试代码#include <stdio.h>int main(int argc, const char *argv[]){ int a[] = {2,3,6,7,10}; int b[] = {1,4,5,8,9}; int c[10]; int index_a = 0; int index_b = 0; int index_c = 0; for (; index_a < 5 && index_b < 5; index_c ++) { i

测试代码#include <stdio.h>#include <math.h>#include <unistd.h>#define N 40int main(int argc, const char * argv[]){ float f; float ret; int i; for (f = 0.0; f < 6.28 * 10; f += 1.0 / N * 4) { ret = sin(f) + 1; for (i = 0;