1008. Elevator (20)
The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.
For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.
Input Specification:
Each input file contains one test case. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100.
Output Specification:
For each test case, print the total time on a single line.
Sample Input:3 2 3 1Sample Output:
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#include<iostream> using namespace std; int main() { int i; int m,now,pre,total; cin>>m; pre=0; total=0; for(i=0;i<m;i++){ cin>>now; if(now>pre){ total+=(now-pre)*6; pre=now; } else{ total+=(pre-now)*4; pre=now; } } total+=5*m; cout<<total<<endl; }

本文介绍了一个基于电梯调度的问题,通过给定楼层请求列表来计算完成所有请求所需的总时间。考虑到电梯上行和下行的时间差异及每层停留时间,提供了一段C++实现代码。
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