//10^5为10的5次方
#include <cstdio>
using namespace std;
int main(){
int nCase;
scanf("%d",&nCase);
while(nCase--){
int a,b,c,d;
scanf("%d %d %d %d",&a,&b,&c,&d);
if(b-a==c-b&&c-b==d-c){
int result;
result=2*d-c;
printf("%d %d %d %d %d\n",a,b,c,d,result);
}else{
int result;
result=d*(d/c);
printf("%d %d %d %d %d\n",a,b,c,d,result);
}
}
return 0;
}
poj1658 Eva's Problem!
最新推荐文章于 2020-03-30 16:07:58 发布