PAT-A1065 A+B and C-优快云博客

本文介绍了一个编程挑战题目，要求实现一个程序来判断三个给定整数A、B和C是否满足A+B>C。文章提供了输入输出规范及示例，并给出了一段示例代码。

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1065 A+B and C (64bit)（20 分）

Given three integers A, B and C in [−263,263], you are supposed to tell whether A+B>C.

Input Specification:

The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

#include <iostream>
int main()
{
	int n;
	scanf("%d", &n);
	long long a, b, c;
	for(int i = 0; i < n; i++){
		scanf("%lld%lld%lld", &a, &b, &c);
		printf("Case #%d: ", i + 1);
		long long res = a + b;    //有点疑问，这个res = a + b 必须写，写在if条件里面就报错？
		if(a > 0 && b > 0 && res < 0){
	 		printf("true");
		}
		else if(a < 0 && b < 0 && res >= 0) printf("false");
		else if(res > c) printf("true");
		else printf("false");
		printf("\n");
	}
	return 0;
}