Search Insert Position

最新推荐文章于 2023-05-31 00:05:53 发布

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本文深入解析了二分查找算法的原理、实现过程及其在解决数组搜索问题中的高效应用。通过具体示例和代码实现，展示了如何利用二分查找优化搜索效率，并探讨了其在实际场景中的具体应用。

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Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume NO duplicates in the array.

Have you met this question in a real interview? Yes
Example
[1,3,5,6], 5 → 2

[1,3,5,6], 2 → 1

[1,3,5,6], 7 → 4

[1,3,5,6], 0 → 0

二分查找!!!

public class Solution {
    public int searchInsert(int[] A, int target) {
        if (A == null || A.length == 0) {
            return 0;
        }
        int start = 0, end = A.length - 1;

        while (start + 1 < end) {
            int mid = start + (end - start) / 2;
            if (A[mid] == target) {
                return mid;
            } else if (A[mid] < target) {
                start = mid;
            } else {
                end = mid;
            }
        }

        if (A[start] >= target) {
            return start;
        } else if (A[end] >= target) {
            return end;
        } else {
            return end + 1;
        }
    }
}