Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
思路:类似归并排序,双指针扫描链表,值小的,就往新链表后面放,最后补齐多余的链表
class Solution {
public:
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
ListNode pre(0);
ListNode *p = ⪯
while (l1&&l2){ //有一个为0 就出局
if (l1->val > l2->val){
p->next = l2;
p = l2;
l2 = l2->next;
}
else{
p->next = l1;
p = l1;
l1 = l1->next;
}
}
if (l1) p->next = l1;
if (l2) p->next = l2;
return (&pre)->next;
}
};