输出任意一年的年历（闲来没事，写了一个小程序）

此程序可以输出1~9999年（其实再往后也可以）的任意一年的年历，和终端里的一模一样。

/*
 *输出任意1～9999一年年历
 */

#include <stdio.h>
#include <stdlib.h>

#define OK 1;
#define ERROR 0;

/*判断闰年*/
int judgeLeap(int year)
{
    if(year < 1800)
    {
        if(year%4 == 0)
            return 1;
        else
            return 0;
    }
    else
    {
        if((year%4 == 0 && year%100 != 0) || (year%400 == 0))
            return 1;
        else
            return 0;
    }
}

/*获取1～year这些年中的闰年数*/
int getCountofLeap(int year)
{
    int count = 0;
    int i = 1;

    for(; i < year; i++)
    {
        if(judgeLeap(i))
            count ++;
    }

    return count;
}

/*获取该年每月第一天位置*/
int getFirstDay(int year, long int * FirstDay)
{
    if(year < 1 || year > 9999)//入参判断
    {
        printf("错误！年份应该在1～9999！\n");
        exit(-1);
    }

    int FirstDay1 = 6;//初始化公元1年第一天位置
    int LastDay[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};//平年每月天数
    int LeapCount = getCountofLeap(year);//1～year之间的闰年数

    //printf("leapcount = %d\n",LeapCount);

    long int temp = 365*(year-1);
    if(year > 1752)
        temp = temp - 11;

    FirstDay[1] = (temp+LeapCount+FirstDay1)%7;//该年第一个月第一天的位置
    
    if(judgeLeap(year))//闰年二月特殊考虑
        LastDay[2] = 29;
    if(year == 1752)
        LastDay[9] = 19;

    int i = 2;
    for(; i < 13; i++)//获取其他月份的第一天位置
    {
        FirstDay[i] = (LastDay[i-1]+FirstDay[i-1])%7;
    }

    return OK;
}

/*输出一年*/
int printYear(int year)
{
    if(year < 1 || year > 9999)//入参判断
    {
        printf("错误！年份应该在1～9999！\n");
        exit(-1);
    }

    char Month[12][10] = {"一月","二月","三月","四月","五月","六月","七月","八月","九月","十月","十一月","十二月"};
    int oneYear[12][6][7] = {};
    long int FirstDay[13] = {0};
    int LastDay[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
    
    getFirstDay(year, FirstDay);

    if(judgeLeap(year))
        LastDay[2] = 29;
    
    int month = 0, week = 0, day = 0, first = 1, last = 1;
    for(month = 0; month < 12; month++)
    {
        first = 1; last = 1;
        for(week = 0; week < 6; week++)
        {
            for(day = 0; day < 7; day++)//输出一周
            {
                if( first > FirstDay[month+1] && last <= LastDay[month+1])
                {
                    oneYear[month][week][day] = last;
                    if(year == 1752 && month == 8 && last == 2)//1752年9月特殊考虑
                        last = last + 11;
                    last ++;
                }
                else
                    oneYear[month][week][day] = 0;
                first ++;
            }
        }
    }

    //printf("%d\n",oneYear[1][0][6]);

    int i = 0, j = 0;
    for(i = 0; i < 4; i++)
    {
        printf("\t %s\t\t\t %s\t\t\t %s\n",Month[j],Month[j+1],Month[j+2]);
        printf(" 日 一 二 三 四 五 六\t 日 一 二 三 四 五 六\t 日 一 二 三 四 五 六\n");
        for(week = 0; week < 6; week++)
        {
            for(month = j; month < j+3; month++)
            {
                for(day = 0; day < 7; day++)//输出一周
                {
                    if(oneYear[month][week][day] == 0)
                        printf("%3c",' ');
                    else
                        printf("%3d",oneYear[month][week][day]);
                }
                printf("\t");
            }
            printf("\n");
        }
        j = j+3;
    }

    return 0;
}

int main(int argc, char * argv[])
{
    int year = 1;

    printf("请输入一个年份：");
    scanf("%d",&year);

    printf("\n\t\t\t\t%d年\n\n",year);

    printYear(year);

    return 0;
}

执行效果：