class Solution:
# @param {integer} x
# @return {integer}
def reverse(self, x):
max=0x7fffffff
min=-0x80000000
flag=False
if x<0:
flag=True
x=-x
mystr=str(x)[::-1]
y=int(mystr,10)
if flag:
y=-y
if y>max or y <min:
return 0
else:
return y
Reverse Integer
最新推荐文章于 2022-09-18 19:57:18 发布