WEBService访问

最新推荐文章于 2023-10-30 17:14:18 发布

原创最新推荐文章于 2023-10-30 17:14:18 发布 · 230 阅读

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这段代码展示了如何使用Java的HttpURLConnection类进行POST请求，访问WebService。它设置了请求头，编码方式，并发送XML格式的SOAP请求数据。接收到响应后，将其解码并打印出来。

public static void test1(String param) throws Exception{
	URL wsUrl = new URL("URL");
    HttpURLConnection conn = (HttpURLConnection) wsUrl.openConnection();//
    conn.setDoInput(true);
    conn.setDoOutput(true);
    conn.setRequestMethod("POST");
    conn.setRequestProperty("Content-Type", "text/xml;charset=UTF-8");
    OutputStream os = conn.getOutputStream();
    BASE64Encoder base64en = new BASE64Encoder();
    String soap = "<soapenv:Envelope xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:q0=\"http://service.zt.com/\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\">" + 
                  "<soapenv:Body> <q0:方法名><arg0>" + base64en.encode(param.getBytes("utf-8")) + "</arg0>  </q0:方法名> </soapenv:Body> </soapenv:Envelope>";
    os.write(soap.getBytes());
    InputStream is = conn.getInputStream();
    byte[] b = new byte[1024];
    int len = 0;
    String s = "";
    while((len = is.read(b)) != -1){
        String ss = new String(b,0,len,"UTF-8");
        s += ss;
    }
    System.out.println(s);
    is.close();
    os.close();
    conn.disconnect();
}