If the elements of the array are pointers,then it is necessary to apply for memory for each element

A pointer array is an array in which each element is a pointer

The code than I wrote by myself

#include<stdio.h>
#include<stdlib.h>
int main() {
    int n, i = 0;
    scanf("%d", &n);
    char* StringArray[n];
    while (i < n) {
        StringArray[i] = malloc(1000);
        scanf("%s", StringArray[i]);
        i++;
    }
    for (i = 0; i < n; i++) {
        printf("%s\n", StringArray[i]);
    }
    return 0;
}

Test

Exceptional situation

A static array refers to an array whose size is fixed and cannot be changed during the execution of a program.

If the array is static,and the pointer points to a constant,then there is no need to apply for memory for it.

Just like the following

#include<stdio.h>
int main() {
    char* arr[3];
    arr[0] = "Hello";
    arr[1] = "World";
    arr[2] = "Ubuntu";
    printf("%s %s %s\n", arr[0], arr[1], arr[2]);
    arr[1] = arr[0];
    arr[2] = arr[0];
    printf("%s %s %s\n", arr[0], arr[1], arr[2]);
    return 0;
}