C 简单枚举类型——植物与颜色 SDUT

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Description

请定义具有red, orange, yellow, green, blue, violet六种颜色的枚举类型color，根据输入的颜色名称，输出以下六种植物花朵的颜色：
Rose(red), Poppies(orange), Sunflower(yellow), Grass(green), Bluebells(blue), Violets(violet)。如果输入的颜色名称不在枚举类型color中，例如输入purple，请输出I don’t know about the color purple.

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Input

输入数据有多行，每行有一个字符串代表颜色名称，颜色名称最多30个字符，直到文件结束为止。

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Output

输出对应颜色的植物名称，例如：Bluebells are blue. 如果输入的颜色名称不在枚举类型color中，例如purple, 请输出I don’t know about the color purple.

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Sample
Input

blue
yellow
purple

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Output

Bluebells are blue.
Sunflower are yellow.
I don’t know about the color purple.

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Hint

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枚举简单但是操作复杂，只需要与已有数据一一对比，找到相对应的数据

#include <stdio.h>
#include <string.h>
enum color{red,orange,yellow,green,blue,violet,no}w;

  int main()
  {
     char a[31];
     while(gets(a))
     {
         if(strcmp(a,"red")==0)
            w=red;
           else if(strcmp(a,"orange")==0)
            w=orange;
            else if(strcmp(a,"yellow")==0)
            w=yellow;
            else if(strcmp(a,"green")==0)
            w=green;
            else if(strcmp(a,"blue")==0)
            w=blue;
            else if(strcmp(a,"violet")==0)
            w=violet;
            else w = no;
            switch(w)
            {
                case red:printf("Rose are red.\n");break;
                case orange:printf("Poppies are orange.\n");break;
                case yellow:printf("Sunflower are yellow.\n");break;
                case green:printf("Grass are green.\n");break;
                case blue:printf("Bluebells are blue.\n");break;
                case violet:printf("Violets are violet.\n");break;
                case no:
                    printf("I don't know about the color %s.\n",a);
            }
     }

      return 0;
  }