Problem Description
请定义具有red, orange, yellow, green, blue, violet六种颜色的枚举类型color,根据输入的颜色名称,输出以下六种植物花朵的颜色:
Rose(red), Poppies(orange), Sunflower(yellow), Grass(green), Bluebells(blue), Violets(violet)。如果输入的颜色名称不在枚举类型color中,例如输入purple,请输出I don’t know about the color purple.
Input
输入数据有多行,每行有一个字符串代表颜色名称,颜色名称最多30个字符,直到文件结束为止。
Output
输出对应颜色的植物名称,例如:Bluebells are blue. 如果输入的颜色名称不在枚举类型color中,例如purple, 请输出I don’t know about the color purple.
Example Input
blue
yellow
purple
Example Output
Bluebells are blue.
Sunflower are yellow.
I don't know about the color purple.
Hint
请用枚举类型实现。
代码
#include <stdio.h>
#include <string.h>
enum color {
red, orange, yellow, green, blue, violet,no
}co;//co枚举变量
int main()
{
char str[31];
while (~scanf("%s", str))
{
if (strcmp(str, "red")==0)
co = red;
else if (strcmp(str, "orange")==0)
co = orange;
else if (strcmp(str, "yellow")==0)
co = yellow;
else if (strcmp(str, "green")==0)
co = green;
else if (strcmp(str, "blue")==0)
co = blue;
else if (strcmp(str, "violet")==0)
co = violet;
else
co = no;
switch (co) {
case red:printf("Rose are red.\n"); break;
case orange:printf("Poppies are orange.\n"); break;
case yellow:printf("Sunflower are yellow.\n"); break;
case green:printf("Grass are green.\n"); break;
case blue:printf("Bluebells are blue.\n"); break;
case violet:printf("Violets are violet.\n"); break;
case no:printf("I don't know about the color %s.\n", str); break;
}
}
return 0;
}