Question
Given preorder and inorder traversal of a tree, construct the binary tree.
Code
public TreeNode get(int[] preorder, int[] inorder, int i, int ileft, int iright) {
if (ileft > iright) {
return null;
}
int t = ileft;
for (t = ileft; t <= iright && inorder[t] != preorder[i]; t++) ;
TreeNode root = new TreeNode(preorder[i]);
root.left = get(preorder, inorder, i + 1, ileft, t - 1);
root.right = get(preorder, inorder, t - ileft + i + 1, t + 1, iright);
return root;
}
public TreeNode buildTree(int[] preorder, int[] inorder) {
if (preorder.length != inorder.length || preorder.length < 1) {
return null;
}
return get(preorder, inorder, 0, 0, inorder.length - 1);
}