Reverse Integer

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本文介绍了一种整数翻转算法的实现方法，包括如何处理输入整数的符号、翻转过程中可能出现的溢出问题，并给出了具体的Python代码实现。

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Reverse digits of an integer.

Example1: x = 123, return 321
Example2: x = -123, return -321

click to show spoilers.

Have you thought about this?
Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!

If the integer’s last digit is 0, what should the output be? ie, cases such as 10, 100.

Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?

For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

Reverse digits of an integer.

Example1: x = 123, return 321
Example2: x = -123, return -321

click to show spoilers.

Have you thought about this?
Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!

If the integer’s last digit is 0, what should the output be? ie, cases such as 10, 100.

Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?

For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

注意需要判断是否会溢出，若益处，则返回0

class Solution(object):
    def reverse(self, x):
        """
        :type x: int
        :rtype: int
        """
        num = 0
        if abs(x) <= 9:
            return x
        abs_x = abs(x)
        while abs_x != 0:
            num = 10*num + abs_x % 10
            abs_x = abs_x/10

        if num >  0x7fffffff:
            return 0
        else:
            return num if x > 0 else -num