ZigZag Conversion

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本文介绍了一种将字符串以Z字形方式排列并按行读取的方法。通过一个Python类和方法实现，输入为字符串和行数，输出为转换后的字符串。示例中使用“PAYPALISHIRING”字符串展示如何进行转换。

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The string “PAYPALISHIRING” is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line: “PAHNAPLSIIGYIR”
Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);
convert(“PAYPALISHIRING”, 3) should return “PAHNAPLSIIGYIR”.

class Solution(object):
    def convert(self, s, numRows):
        """
        :type s: str
        :type numRows: int
        :rtype: str
        """
        length = len(s)
        rows = []
        for i in range(numRows):
            rows.append([])

        i = 0
        while i < length:
            for idx in range(numRows):
                if i < length:
                    rows[idx].append(s[i])
                    i += 1
            for idy in range(1, numRows-1)[::-1]:
                if i < length:
                    rows[idy].append(s[i])
                    i += 1
        for idz in range(1, numRows):
            rows[0].extend(rows[idz]

        return ''.join(i for i in rows[0])