codeforces 441A Valera and Antique Items

最新推荐文章于 2019-05-05 16:31:00 发布

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#英语

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Valera作为一位收藏家，计划用有限的资金从几位卖家手中购得一件古董。面对不同卖家提供的多种古董及其当前拍卖价格，Valera需要找出能够负担得起的最低价古董，从而确定可以从哪些卖家处成功竞拍。

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Valera is a collector. Once he wanted to expand his collection with exactly one antique item.

Valera knows n sellers of antiques, the i-th of them auctioned ki items. Currently the auction price of the j-th object of the i-th seller is sij. Valera gets on well with each of the n sellers. He is perfectly sure that if he outbids the current price of one of the items in the auction (in other words, offers the seller the money that is strictly greater than the current price of the item at the auction), the seller of the object will immediately sign a contract with him.

Unfortunately, Valera has only v units of money. Help him to determine which of the n sellers he can make a deal with.

Input

The first line contains two space-separated integers n, v (1 ≤ n ≤ 50; 104 ≤ v ≤ 106) — the number of sellers and the units of money the Valera has.

Then n lines follow. The i-th line first contains integer ki (1 ≤ ki ≤ 50) the number of items of the i-th seller. Then go ki space-separated integers si1, si2, ..., siki (104 ≤ sij ≤ 106) — the current prices of the items of the i-th seller.

Output

In the first line, print integer p — the number of sellers with who Valera can make a deal.

In the second line print p space-separated integers q1, q2, ..., qp (1 ≤ qi ≤ n) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order.

        Examples
      

          input
        
3 50000
1 40000
2 20000 60000
3 10000 70000 190000

          output
        
3
1 2 3

          input
        
3 50000
1 50000
3 100000 120000 110000
3 120000 110000 120000

          output
        
0

Note

In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.

In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the auction too big for him.

题我没翻译明白，唉~，还是英语不好，翻译清楚了，就明白有多简单了。

#include<cstdio>
#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;
int main()
{
    int n,v;
    cin>>n>>v;
    int a[100],t=0;
    for(int i=0; i<n; i++)
    {
        int k,x;
        bool flag=false;
        cin>>k;
        for(int j=0; j<k; j++)
        {
            cin>>x;
            if(v>x)
                flag=true;
        }
        if(flag)
            a[t++]=i+1;
    }
    cout<<t<<endl;
    for(int i=0; i<t; i++)
    {
        if(i==0)
            cout<<a[i];
        else
            cout<<" "<<a[i];
    }
    if(t)
        cout<<endl;
    return 0;
}