PAT甲级真题 1014 Waiting in Line (30分) C++实现（题意有坑，测试点2、4、5会报错）

题目

Suppose a bank has N windows open for service. There is a yellow line in front of the windows which devides the waiting area into two parts. The rules for the customers to wait in line are:
The space inside the yellow line in front of each window is enough to contain a line with M customers. Hence when all the N lines are full, all the customers after (and including) the (NM+1)st one will have to wait in a line behind the yellow line.
Each customer will choose the shortest line to wait in when crossing the yellow line. If there are two or more lines with the same length, the customer will always choose the window with the smallest number.
Customer[i] will take T[i] minutes to have his/her transaction processed.
The first N customers are assumed to be served at 8:00am.
Now given the processing time of each customer, you are supposed to tell the exact time at which a customer has his/her business done.
For example, suppose that a bank has 2 windows and each window may have 2 custmers waiting inside the yellow line. There are 5 customers waiting with transactions taking 1, 2, 6, 4 and 3 minutes, respectively. At 08:00 in the morning, customer1 is served at window1 while customer2 is served at window2. Customer3 will wait in front of window1 and customer4 will wait in front of window2. Customer5 will wait behind the yellow line.
At 08:01, customer1 is done and customer5 enters the line in front of window1 since that line seems shorter now. Customer2 will leave at 08:02, customer4 at 08:06, customer3 at 08:07, and finally customer5 at 08:10.
Input
Each input file contains one test case. Each case starts with a line containing 4 positive integers: N (<=20, number of windows), M (<=10, the maximum capacity of each line inside the yellow line), K (<=1000, number of customers), and Q (<=1000, number of customer queries).
The next line contains K positive integers, which are the processing time of the K customers.
The last line contains Q positive integers, which represent the customers who are asking about the time they can have their transactions done. The customers are numbered from 1 to K.
Output
For each of the Q customers, print in one line the time at which his/her transaction is finished, in the format HH:MM where HH is in [08, 17] and MM is in [00, 59]. Note that since the bank is closed everyday after 17:00, for those customers who cannot be served before 17:00, you must output “Sorry” instead.
Sample Input
2 2 7 5
1 2 6 4 3 534 2
3 4 5 6 7
Sample Output
08:07
08:06
08:10
17:00
Sorry

思路

用队列queue模拟排队情况。

使用数据结构如下：

1. 用结构体C存储顾客编号和所需时间：struct C{id; t};
2. 用队列数组表示所有窗口排队情况：vector<queue<C> > window(n);
3. 用队列存储等待区域顾客信息：queue<C> wait;
4. 用数组time记录顾客完成时间:vector<int> time(k+1);

步骤如下：

1. 读入顾客信息，将顾客尽可能排到各个窗口；剩下的加入等待队列当中；
2. 遍历各窗口队头，找出当前最短时间；各队头均减去该最短时间；对所有时间为0队头，将其出队，记录其结束时间到time[]中，并将等待区顾客（如果有的话）入队；
3. 若当前最快的顾客结束时间已达17:00，把当前所有窗口正在进行的服务处理完即结束（此处易错）；
4. 最后对于查询的人，若在time[]有记录则直接输出；若无记录， 则输出“sorry”。

注意坑

17:00截止指的是开始时间而不是结束时间，若17:00前已经开始，无论时间多久都要服务完（题目中给的输出时间范围，最大可以是17:59）。否则测试点2、4、5会报错。

例如测试用例：

2 1 3 3
1 540 540
1 2 3

应输出：

08:01
17:00
17:01

代码

#include <iostream>
#include <vector>
#include <queue>
#