A + B Problem II

A + B Problem II

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 276437 Accepted Submission(s): 53359

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

2
1 2
112233445566778899 998877665544332211

Sample Output

Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

#include<stdio.h>
#include<stdlib.h>

int main(){
    int n,t,i,j,b,start,x,end,end1,start1,a1,max,sum,max1;
    scanf("%d",&t);
    for(i=1;i<=t;i++){
        scanf("%d%d",&n,&a1);
        max=a1;
        max1=a1;
        start=1;
        start1=1;
        end1=1;
        end=1;
        printf("Case %d:\n",i);
        for(j=2;j<=n;j++){
            scanf("%d",&b);
            
            if(max1<0){
                    start1=j;
                    end1=j;
                    max1=b;
            }
            else {
                max1+=b;
                end1=j;
            }
            if(max<max1){
                max=max1;
                start=start1;
                end=end1;
            }
        }
        
        printf("%d %d %d\n",max,start,end);
        if(i!=t)
        printf("\n");
    }
}