题目:
Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note:
You are not suppose to use the library’s sort function for this problem.
click to show follow up.
Follow up:
A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0’s, 1’s, and 2’s, then overwrite array with total number of 0’s, then 1’s and followed by 2’s.
Could you come up with an one-pass algorithm using only constant space?
java代码
public void sortColors(int[] A) {
int start = 0;//指向数组的头
int cur = 0;//指向当前数组元素的指针
int end = A.length - 1;//指向数组的尾
while(cur<=end){
if(A[cur] == 0){//当前元素为0
int temp = A[start];
A[start] = A[cur];
A[cur] = temp;
cur++;
start++;
}else if(A[cur] == 2){//当前元素为2
int temp = A[end];
A[end] = A[cur];
A[cur] = temp;
end--;
}else{//当前元素为1,
cur++;
}
}
}