黑猫5027的博客

今年暑假不AC Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 40706    Accepted Submission(s): 21773 Problem Description “今年暑假不AC？” “是的。

Best Cow Line Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 15444   Accepted: 4363 Description FJ is about to take his N (1 ≤ N ≤ 2,000) cows to the annu

Saruman's Army Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6197   Accepted: 3165 Description Saruman the White must lead his army along a straight pa

Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 35249   Accepted: 11392 Description Farmer John wants to repair a small length of the fence ar

表示这道题目今天模拟的时候做了将近三个小时都没有做出来，细节错误实在是太多了，心累啊。唉，最后还是看了一下别人的题解，打算明天好好在重新一份 #include #include #include using namespace std; const int inf = 0x3f3f3f3f; const int maxn = 1000 + 50; int cnt, n

都说用dp和贪心的。。。不过我也用的贪心的思想。。。 反正就是每次取和现在vector中存放的高度里面相差最近的那个高度，然后修改就好了，如果vector中没有符合的，那就把他放入vector中再sort一下就好了 最后答案就是v.len