day 57

2535.数组元素和与数字和的绝对差

int differenceOfSum(int* nums, int numsSize) {
    int x=0,y=0;
    for(int i=0;i<numsSize;i++){
        x+=nums[i];
        while(nums[i]!=0){
            y+=nums[i]%10;
            nums[i]/=10;
        }
    }
    return abs(x-y);
}

3065.超过阈值的最小操作数I

int minOperations(int* nums, int numsSize, int k) {
    int t=0;
    for(int i=0;i<numsSize;i++){
        if(nums[i]<k){
            t++;
        }
    }
    return t;
}