题目链接:https://www.lanqiao.cn/courses/2786/learning/?id=67813
答案:2658417853
解析:按照题目要求直接暴力加即可,代码如下:
//#define local
#include<cstdio>
#include<iostream>
using namespace std;
typedef long long ll;
//用于检查数n是否含2或0或1或9
bool cheak(int n){
while(n){
int t=n%10;
if(t==2||t==0||t==1||t==9)
return true;
n=n/10;
}
return false;
}
int main(){
#ifdef local
freopen("data.in","rb",stdin);
freopen("data.out","wb",stdout);
#endif
ll res=0;
//ll sum=0;
for(int i=1;i<=2019;i++){
if(cheak(i)){
res+=i*i;
}
}
cout<<res;
return 0;
}