爬虫爬取51job python职位相关信息

最新推荐文章于 2023-10-19 11:34:51 发布

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最新推荐文章于 2023-10-19 11:34:51 发布

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分类专栏：爬虫系列

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本文介绍了一个简单的Python爬虫程序，用于抓取51job网站上Python岗位的详细信息，包括职位名称、公司、工作年限及薪水等。

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分析如下:

1.(深圳)搜索页:
    https://search.51job.com/list/040000,000000,0000,00,9,99,%2520,2,1.html?lang=c&stype=&postchannel=0000&workyear=99&cotype=99&degreefrom=99&jobterm=99&companysize=99&providesalary=99&lonlat=0%2C0&radius=-1&ord_field=0&confirmdate=9&fromType=&dibiaoid=0&address=&line=&specialarea=00&from=&welfare=

2.输入python岗位搜索后:
    https://search.51job.com/list/040000,000000,0000,00,9,99,python,2,1.html?lang=c&stype=&postchannel=0000&workyear=99&cotype=99&degreefrom=99&jobterm=99&companysize=99&providesalary=99&lonlat=0%2C0&radius=-1&ord_field=0&confirmdate=9&fromType=&dibiaoid=0&address=&line=&specialarea=00&from=&welfare=

3.每页只改变2,后面的数字

代码如下:

from urllib.request import *
import re
from lxml import etree


class Job(object):
    # 1.发送首页请求
    def __init__(self):
        # self.position = input("请输入你想要查询的岗位:")
        self.start_page = int(input("请输入你要爬的起始页:"))
        self.end_page = int(input("请输入你要爬的结束页:"))
        # 请求报头
        self.headers = {"User-Agent": "Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.1; Trident/5.0;"}

    def get_page_html(self):
        """爬虫开始,获取每页的网页源码"""
        print('开始爬取数据')
        for page in range(self.start_page, self.end_page + 1):
            url = 'https://search.51job.com/list/040000,000000,0000,00,9,99,' + 'python' + ',2,' + str(page) + '.html?lang=c&stype=&postchannel=0000&workyear=99&cotype=99&degreefrom=99&jobterm=99&companysize=99&providesalary=99&lonlat=0%2C0&radius=-1&ord_field=0&confirmdate=9&fromType=&dibiaoid=0&address=&line=&specialarea=00&from=&welfare='
            # print(url)

            # 防止请求网页页数过大而报错
            try:
                print("正在爬取第%d页..."%page)
                request = Request(url, headers=self.headers)
                response = urlopen(request)

                # 得到网页源码
                html = response.read().decode("gbk")
                self.get_positon_html(html,page)
            except:
                pass

    def get_positon_html(self, html,page):
        """获取每个职位的网页源码"""
        selector = etree.HTML(html)

        # 获取个职位的单独的html
        postion_list = selector.xpath('//p[@class="t1 "][1]//a/@href')
        print('正在保存第%d页的数据...' % page)

        for postion_url in postion_list:
            resquest = Request(postion_url, headers=self.headers)
            response = urlopen(resquest)

            html1 = response.read().decode('gbk')
            self.get_position_info(html1)

    def get_position_info(self, html):

        # 把每个职位的相关信息放入一个字典中
        item = {}

        h1 = re.findall(r'<h1 title=.*?>', html)[0]
        item['职位'] = re.sub('<h1 title="|">', '', h1)

        h2 = re.findall(r'target="_blank" title=.*? ', html)[0]
        item["公司"] = re.sub('target="_blank" title="|" ', '', h2)

        h3 = re.findall(r'<p class="msg ltype" title=.*?>', html)[0]
        item['工作年限'] = re.sub('<p class="msg ltype" title="|&nbsp;|">', '', h3)

        h4 = re.findall(r'<strong>.*?</strong>', html)[1]
        item['薪水'] = re.sub('<strong>|</strong>', '', h4)

        item['分割线'] = '-' *30


        for i in item:
            with open('51job.txt', 'a') as f:
                f.write(item[i]+'\n')


def main():
    job = Job()
    job.get_page_html()


if __name__ == '__main__':
    main()