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最新推荐文章于 2018-07-03 11:53:56 发布

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最新推荐文章于 2018-07-03 11:53:56 发布

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本文链接：https://blog.youkuaiyun.com/yu_ming_cong/article/details/46953875

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本文介绍了一个简单的编程问题：如何判断字符串“wyh”是否为给定字符串的子序列，特别考虑了连续字符被视为单一字符的情况。通过示例输入输出展示了问题场景，并提供了一段C++代码实现解决方案。

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wyh2000 and a string problem

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others)

Problem Description

Young theoretical computer scientist wyh2000 is teaching young pupils some basic concepts about strings.

A subsequence of a string

s is a string that can be derived from

s by deleting some characters without changing the order of the remaining characters. You can delete all the characters or none, or only some of the characters.

He also teaches the pupils how to determine if a string is a subsequence of another string. For example, when you are asked to judge whether

wyh is a subsequence of some string or not, you just need to find a character

w, a

y, and an

h, so that the

w is in front of the

y, and the

y is in front of the

h.

One day a pupil holding a string asks him, "Is

wyh a subsequence of this string?"
However, wyh2000 has severe myopia. If there are two or more consecutive character

vs, then he would see it as one

w. For example, the string

vvv will be seen as

w, the string

vvwvvv will be seen as

www, and the string

vwvv will be seen as

vww.

How would wyh2000 answer this question?

Input

The first line of the input contains an integer

T(T≤105), denoting the number of testcases.

N lines follow, each line contains a string.

Total string length will not exceed 3145728. Strings contain only lowercase letters.

The length of hack input must be no more than 100000.

Output

For each string, you should output one line containing one word. Output

Yes if wyh2000 would consider

wyh as a subsequence of it, or

No otherwise.

Sample Input

4
woshiyangli
woyeshiyangli
vvuuyeh
vuvuyeh

Sample Output

No
Yes
Yes
No

水题还会错，唉，刚开始套了三层循环，一直超时，额，不超时才怪。

#include <iostream>
#define maxn 3145728+5
#include <string.h>
#include <stdio.h>
using namespace std;

char c[maxn],a[4]="wyh";
int main()
{
    int n;
    cin>>n;
    int flag;
    while(n--)
    {  // memset(c,0,sizeof(c));
        scanf("%s",c);
        flag=0;
        int cnt=0;
        int len=strlen(c);
        //cout<<len<<endl;
        c[len]='a';
        c[len+1]='\0';
        for(int i=0; i<len; i++)
        {
            if(c[i]=='v'&&c[i+1]=='v')
            c[i]='w';
            if(c[i]==a[cnt])
            cnt++;
            if(cnt==3)
            break;

        }
        if(cnt==3)
        cout<<"Yes"<<endl;
        else
        cout<<"No"<<endl;
    }
    return 0;
}