连续点击两次返回键,退出当前的程序。代码如下:
private static Boolean isExit = false;
private static Boolean hasTask = false;
Timer tExit = new Timer();
TimerTask task = new TimerTask() {
@Override
public void run() {
isExit = false;
hasTask = true;
}
};
public boolean onKeyDown(int keyCode, KeyEvent event) {
if(keyCode == KeyEvent.KEYCODE_BACK){
if(isExit == false ) {
isExit = true;
Toast.makeText(this, "再按一次退出程序",Toast.LENGTH_SHORT).show();
if(!hasTask) {
tExit.schedule(task, 2000); //两次按下的时间间隔不超过2秒。
}
} else {
finish();
System.exit(0);
}
}
return false;
}