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Count the string
Count the string Time Limit : 2000/1000ms (Java/Other) Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 5 Accepted Submission(s) : 2 Problem Description It is well known原创 2014-04-04 21:34:58 · 1290 阅读 · 0 评论 -
http://poj.org/problem?id=1035
Spell checker Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 19066 Accepted: 6970 Description You, as a member of a development team for a new spell check原创 2014-08-03 10:21:46 · 772 阅读 · 0 评论 -
http://poj.org/problem?id=1598
Excuses, Excuses! Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 3658 Accepted: 1272 Description Judge Ito is having a problem with people subpoenaed for原创 2014-07-28 18:02:49 · 627 阅读 · 0 评论 -
http://poj.org/problem?id=3337
Expression Evaluator Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 1925 Accepted: 594 Description This problem is about evaluating some C-style expressio原创 2014-07-29 10:33:47 · 672 阅读 · 0 评论 -
http://poj.org/problem?id=1503
Integer Inquiry Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 29577 Accepted: 11509 Description One of the first users of BIT's new supercomputer was Chi原创 2014-07-29 13:52:00 · 670 阅读 · 0 评论 -
http://poj.org/problem?id=2408
#include #include #include #include using namespace std; typedef struct { char s[100]; char re_s[100]; }word; word data[30005]; int cnt = 0; typedef struct { int num; int start; }p原创 2014-07-25 19:52:50 · 740 阅读 · 0 评论 -
统计难题
统计难题 Time Limit : 4000/2000ms (Java/Other) Memory Limit : 131070/65535K (Java/Other) Total Submission(s) : 3 Accepted Submission(s) : 2 Problem Description Ignatius最近遇到一个难题,老师交给他很多单词(只原创 2014-04-03 08:14:15 · 739 阅读 · 0 评论 -
Hat’s Words
Hat’s Words Time Limit : 2000/1000ms (Java/Other) Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 6 Accepted Submission(s) : 2 Problem Description A hat’s word is a word原创 2014-04-05 13:20:30 · 1254 阅读 · 0 评论 -
亲和串
亲和串 Time Limit : 3000/1000ms (Java/Other) Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 14 Accepted Submission(s) : 3 Problem Description 人随着岁数的增长是越大越聪明还是越大越笨,这是一个值得全世原创 2014-04-05 16:19:14 · 1507 阅读 · 0 评论 -
Number Sequence
Number Sequence Time Limit : 10000/5000ms (Java/Other) Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 5 Accepted Submission(s) : 4 Problem Description Given two sequenc原创 2014-04-04 19:57:51 · 736 阅读 · 0 评论 -
Oulipo
Oulipo Time Limit : 2000/1000ms (Java/Other) Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 11 Accepted Submission(s) : 4 Problem Description The French author Georg原创 2014-04-03 23:01:56 · 1069 阅读 · 0 评论 -
TEX Quotes
TEX Quotes Time Limit : 2000/1000ms (Java/Other) Memory Limit : 20000/10000K (Java/Other) Total Submission(s) : 3 Accepted Submission(s) : 3 Problem Description TEX is a typesetting la原创 2014-04-02 20:19:03 · 943 阅读 · 0 评论 -
Phone List
Phone List Time Limit : 2000/1000ms (Java/Other) Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 12 Accepted Submission(s) : 3 Problem Description Given a list of p原创 2014-04-02 21:11:04 · 763 阅读 · 0 评论 -
Message Decowding
Message Decowding Time Limit : 2000/1000ms (Java/Other) Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 4 Accepted Submission(s) : 4 Problem Description The cows are th原创 2014-04-02 19:42:35 · 840 阅读 · 0 评论 -
Period 和 字符串周期
Period Time Limit : 6000/3000ms (Java/Other) Memory Limit : 60000/30000K (Java/Other) Total Submission(s) : 16 Accepted Submission(s) : 3 Problem Description For each prefix of a given原创 2014-04-05 17:37:22 · 1864 阅读 · 0 评论 -
KMP 算法
KMP 算法 与 朴素算法相比少了不必要的重复工作,比如ABABCD串在C处失配应从第二个A处匹配,不是第一个A处匹配。所以KMP的关键是状态转移表(预处理时间是0(M)),总的时间复杂度是0(M + N)。 状态转移就是模式串每个位置的最大相等子串。 前提: #include #include #include using namespace std; char w[10010];原创 2014-04-03 23:58:37 · 1078 阅读 · 0 评论