题目1008:最短路径问题
时间限制:1 秒
内存限制:32 兆
特殊判题:否
提交:5199
解决:1655
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题目描述:
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给你n个点,m条无向边,每条边都有长度d和花费p,给你起点s终点t,要求输出起点到终点的最短距离及其花费,如果最短距离有多条路线,则输出花费最少的。
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输入:
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输入n,m,点的编号是1~n,然后是m行,每行4个数 a,b,d,p,表示a和b之间有一条边,且其长度为d,花费为p。最后一行是两个数 s,t;起点s,终点t。n和m为0时输入结束。
(1<n<=1000, 0<m<100000, s != t)
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输出:
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输出 一行有两个数, 最短距离及其花费。
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样例输入:
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3 2 1 2 5 6 2 3 4 5 1 3 0 0
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样例输出:
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9 11
import java.util.ArrayList; import java.util.Arrays; import java.util.List; import java.util.Scanner; public class Main { /** * @param args */ public static void main(String[] args) { Scanner scanner = new Scanner(System.in); while( scanner.hasNext() ){ int n = scanner.nextInt(); int m = scanner.nextInt(); if(n == 0 && m == 0) break; List<Edge> edges[] = new ArrayList[n+1]; for (int i = 1; i < edges.length; i++) { edges[i] = new ArrayList<Edge>(); } Edge edgetmps[] = new Edge[1001]; for (int i = 0; i < edgetmps.length; i++) { edgetmps[i] = new Edge(); } while(m-- != 0){ int a = scanner.nextInt(); int b = scanner.nextInt(); int d = scanner.nextInt(); int p = scanner.nextInt(); edgetmps[a] = new Edge(); edgetmps[a].d = d; edgetmps[a].p = p; edgetmps[a].next = b; edges[a].add(edgetmps[a]); edgetmps[b] = new Edge(); edgetmps[b].d = d; edgetmps[b].p = p; edgetmps[b].next = a; edges[b].add(edgetmps[b]); } int s = scanner.nextInt(); int e = scanner.nextInt(); int Dis[] = new int[1001]; int cost[] = new int[1001]; boolean mark[] = new boolean[1001]; Arrays.fill(mark, false); Arrays.fill(Dis, -1); Arrays.fill(cost, 0); Dis[s] = 0; mark[s] = true; int newP = 1; for (int i = 1; i < n; i++) { for (int j = 0; j < edges[newP].size(); j++) { int t = edges[newP].get(j).next; int d = edges[newP].get(j).d; int p = edges[newP].get(j).p; if(mark[t] == true) continue; if(Dis[t] == -1 || Dis[t] > Dis[newP] + d || (Dis[t] == Dis[newP] + d && cost[t] > cost[newP] + p)){ Dis[t] = Dis[newP] + d; cost[t] = cost[newP] + p; } } int min = 123123123; for (int j = 1; j <=n; j++) { if(mark[j] == true) continue; if(Dis[j] == -1) continue; if(Dis[j] < min){ min = Dis[j]; newP = j; } } mark[newP] = true; } System.out.println(Dis[e]+" "+cost[e]); } } public static class Edge{ int next; int p; int d; } } /************************************************************** Problem: 1008 User: yihukurama Language: Java Result: Accepted Time:370 ms Memory:27484 kb ****************************************************************/