题目描述:
代码实现:
#include<iostream>
using namespace std;
int arr1[1010];
int arr2[1010] = { 0 };
int arr3[1010] = { 0 };
int main()
{
int n;
int maxa = 0;
int mina = 1000;
cin >> n;
for (int i = 0; i < n; i++)
{
cin >> arr1[i];
maxa = max(maxa, arr1[i]);
mina = min(mina, arr1[i]);
arr2[arr1[i]]++;
arr3[arr1[i]]++;
}
for (int i = 1; i < maxa + 1; i++)
{
arr2[i] += arr2[i - 1];
}
for (int i = maxa - 1; i >= mina - 1; i--)
{
arr3[i] += arr3[i + 1];
}
for (int i = 0; i < n; i++)
{
if (arr2[arr1[i]] == arr3[arr1[i]])
{
cout << arr1[i];
return 0;
}
}
cout << "-1";
return 0;
}