1.求的和
a,b=2,1
sum=0
t=-1
n=int(input("input:"))
for i in range(1,n+1):
sum=(t**(i+1))*(a/b)+sum
b=a
a=a+1
print("answer is",sum)
2.打印1000以内的完全数
n=[]
for i in range(1,1001):
a=0
for j in range(1,i):
if(i%j==0):
a+=j
if i==a:
n.append(i)
print(n)